(5) (3x - 3x? - 12 + x4 + x) = (2 + x?)
(6*) (a" - a + a?' - a + 1) = (a - 2)
(7*) (4x4 - 5x - 7x + 1) = (4x - 1)
Answers
Answer:
Step-by-step explanation:
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Answer:
Question :-
Divide !
(x⁴+x³-3x²+3x-12) ÷ (2+x²)
(a⁴-a³+a²-a+1) ÷ (a³ - 2)
(4x⁴-5x³-7x+1) ÷ (4x-1)
ANSWER
Solution : -
1.
(x⁴+x³-3x²+3x-12) ÷ (2+x²)
2+x² )x⁴+x³-3x²+3x-12(
This can be written as;
x²+2 )x⁴+x³-3x²+3x-12(x²+x
x⁴ +2x²
(-) (-)
0+x³-5x²+3x
x³ +2x
(-) (-)
0-5x²+x
2.
(a⁴-a³+a²-a+1) ÷ (a³ - 2)
a³-2 )a⁴- a³+a²-a+1(a³+1
a⁴-2a³
(-) (+)
0+ a³+a²-a+1
a³ -2
(-) (+)
a²-a+3
3.
(4x⁴-5x³-7x+1) ÷ (4x-1)
4x-1 )4x⁴-5x³+0-7x+1(x³-x²-(x)/(4)-(29)/(16)
4x⁴-x³
(-) (+)
-4x³+0
-4x³+x²
(+) (-)
- x²-7x
-x² +(x)/(4)
(+) (-)
(-29x)/(4) + 1
(-29x)/(4) + (29)/(16)
(-) (-)
(-13)/(16)