Question

5(3x+4)-8(6×-7)=9x-8​

Answer 1

Answer:

2

Step-by-step explanation:

5(3x+4)-8(6x-7)=9x-8​

=> 15x + 20 - 48x + 56 = 9x -8

=> 76 - 33x = 9x - 8

=> 42x = 84

=> x = 2

Answer 2

Given,

$5(3x+4)-8(6x-7)=9x-8$

We have to find the value of $x$.

We have to identify the constant terms and variable terms.

First we have to move the $x$ terms are LHS side and Constant terms are RHS side.

Now,

$5(3x+4)-8(6x-7)=9x-8$

$15x+20-48x+56=9x-8$

$9x-15x+48x=56+20+8$

$9x+33x=84$

$42x=84$

$x=\frac{84}{42}$

$x=2$

Therefore, the value of $x$ is $2$.