Question

5(3x+y)²+6(3x+y)-8
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Answer 1

Answer:

answer = $45x^{2} + 30xy + 18x + 6y - 8 + 5y^{2}$

Step-by-step explanation:

expand $(3x+y)^{2}$ first

$(3x+y)(3x+y)$ = $9x^{2} + 3xy+3xy+y^{2}$

                         = $9x^{2} +6xy+y^{2}$

$5(3x+y)^{2} + 6(3x+y)-8$

replace  $9x^{2} +6xy+y^{2}$  in $(3x+y)^{2}$

= 5($9x^{2} +6xy+y^{2}$) $+ 6(3x+y)-8$

= $45x^{2} + 30xy + 5y^{2} + 18x + 6y - 8$

reorder : $45x^{2} + 30xy + 18x + 6y - 8 + 5y^{2}$