Math, asked by Anonymous, 6 months ago


ᵂᵃᵗᵉʳ ⁱⁿ ᵃ ᶜᵃⁿᵃˡ, 5.4ᵐ ʷⁱᵈᵉ ᵃⁿᵈ 1.8ᵐ ᵈᵉᵉᵖ, ⁱˢ ᶠˡᵒʷⁱⁿᵍ ʷⁱᵗʰ ᵃ ˢᵖᵉᵉᵈ ᵒᶠ 25 ᵏᵐ/ʰʳ.ᴴᵒʷ ᵐᵘᶜʰ ᵃʳᵉᵃ ᶜᵃⁿ ⁱᵗ ⁱʳʳⁱᵍᵃᵗᵉ ⁱⁿ 40 ᵐⁱⁿᵘᵗᵉˢ, ⁱᶠ 10 ᶜᵐ ᵒᶠ ˢᵗᵃⁿᵈⁱⁿᵍ ʷᵃᵗᵉʳ ⁱˢ ʳᵉᵠᵘⁱʳᵉᵈ ᶠᵒʳ ⁱʳʳⁱᵍᵃᵗⁱᵒⁿ.

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Answers

Answered by ItzDαrkHσrsє
35

\large{\underline{\sf{\blue{Given-}}}}

\begin{cases} \text{Wide \: Of \: Canal \: = \: 504m} \ \  \\{Depth \: Of \: Canal \: = \: 1.8m}\end{cases}

\large{\underline{\sf{\green{To \: Find-}}}}

\begin{cases} \text{Area \: Of \: Irrigation}\end{cases}

\large{\underline{\sf{\purple{Solution-}}}}

\sf{• \: Water \: is \:  flowing \: with \: speed \: of \: 25km/h}

\sf{Thus,}

\sf{In \: 40 \: min, \: water \: will \: flow :}

\implies\sf{ \frac{25}{60}  \times 40}

\large{\boxed{\sf{ \frac{50}{3}km}}}

\sf{As \: per \: Question,}

\boxed{\sf\red{volume \: of \: water \: in \: canal \:  =  \: volume \: of \: irrigation \: area}}

\sf{Hence,}

\boxed{\sf\green{★ \: volume \: of \: canal \:  =  \: l \times b \times h}}

\sf{Placing \: Values}

\implies\sf{504 \times 1.8 \times  \frac{50000}{3 {m}^{3} }}

\sf{Required \: Area \: For \: Standing \: Water \: Is \: 10cm}

\implies\sf{ \frac{5000}{ \frac{50 \times 10}{100} } }

\implies\sf{5.4 \times 0.6 \times 500 \times 10}

\boxed{\sf\purple{★ 16200 {m}^{2} }}

\large{\underline{\sf{\red{Area \: Of \: Irrigation \: Is \: 16200m²}}}}

Answered by SujithaReddy1
3

Step-by-step explanation:

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