Question

5,4,3=18 3,5,3=65 9,6,3=?​

Answer 1

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Given :

5 , 3 , 4 = 18

3 , 5 , 3 = 65

9 , 6 , 3 = ?

Solution :

In the above sequences the first numbers are the sequence of a² , a⁴ , a²........

To solve this question we use the logic as:-

a² + (b + c)(b - c)

where ,

a is the first number of sequence

b is the second number of the sequence

c is the third number of the sequence

lets first take the sequence of

5 , 3 , 4 = ?

a = 5

b = 3

c = 4

substitute in the formula

a² + (b + c)(b - c)

5² + ( 3 + 4)( 3 - 4) = 25 + (7)(-1)

= 25 - 7

= 18

Therefore 5 , 3 , 4 = 18

Lets take second sequence now :

3 , 5 , 3 = ?

a = 3

b = 5

c = 3

substitute in the formula

a⁴ - (b + c)(b - c)

3⁴ - (5 + 3)( 5 - 3) = 81 - (8)(2)

= 81 - 16

= 65

Therefore, 3 , 5 , 3 = 65

Now lets take the third sequence :

9 , 6 , 3 = ?

Take the rule :

a²+ (b + c)(b - c)

9² + (6 + 3)(6 - 3) = 81 + (9)(3)\\

= 81 + 27

= 108

Therefore , 9 , 6 , 3 = 108