Question

5/4 (3x-1)-1(4x-2x/3)=x+7/3
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Answer 1

Answer:

$\frac{5}{4}\left(3x-1\right)-1\cdot \left(4x-2\cdot \frac{x}{3}\right)=x+\frac{7}{3}\quad :\quad x=-\frac{43}{7}\quad \left(\mathrm{Decimal}:\quad x=-6.14285\dots \right)$

Step-by-step explanation:

$\frac{5}{4}\left(3x-1\right)-1\cdot \left(4x-2\cdot \frac{x}{3}\right)=x+\frac{7}{3}$

$\frac{5}{4}\left(3x-1\right)-\left(4x-\frac{2x}{3}\right)=x+\frac{7}{3}$

$\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}$

$\frac{5}{4}\left(3x-1\right)-\left(4x-\frac{2x}{3}\right)-x=x+\frac{7}{3}-x$

$\frac{-7x-15}{12}=\frac{7}{3}$

$\mathrm{Multiply\:both\:sides\:by\:}12$

$\frac{12\left(-7x-15\right)}{12}=\frac{7\cdot \:12}{3}$

$-7x-15=28$

$\mathrm{Add\:}15\mathrm{\:to\:both\:sides}$

$-7x-15+15=28+15$

$-7x=43$

$\mathrm{Divide\:both\:sides\:by\:}-7$

$\frac{-7x}{-7}=\frac{43}{-7}$

$x=-\frac{43}{7}$