Math, asked by goaliitkc, 5 hours ago

5 49 81 - 5 7 ? - 15 13 11​

Answers

Answered by bharat1234567819
2

Step-by-step explanation:

will try my best to give the solution in most detailed manner such that you will be able to understand the solutions quickly ,as well as you will be able to build logic if question’s of these types are asked in future .

That’s enough talk, Let’s start!

Step 1: Initially try to read the question , and think about what all changes are made in each digits as we are moving forward .

Step 2: As you will see that all the digits are square’s of digits , after analysing it once again , you will get that the given digits are squares of odd digits.

Step 3: And we can write odd digits in one more form (2*n+1). But those above digits are square of odd numbers so instead we will write as (2*n+1)^2.

Step 4: So now we just need to substitute values in place of n.

So for n=0,we get (2*0+1)^2=1

for n=1 ,we get (2*1+1)^2=9

for n=2,we get (2*2+1)^2=25

and so on.

I hope you are able to get what i am trying to do .

At last KEEP THINKING !!

and KEEP SMILING!!

The series is (2n+1)^2, where n is a natural number, including 0.

When n = 0, number is 1.

When n = 1, number is 9.

When n = 2, number is 25.

When n = 3, number is 49.

When n = 4, number is 81.

When n = 5, number is 121.

The next will be n = 6, and the number will be 169.

Solve: 1+8=9

9+8×2=9+16=25

25+8×3=25+24=49

49+8×4=49+32=81

81+8×5=81+40=121

121+8×6=121+48=169

169+8×7=169+56=225

Second solution:

1+8=9=3^2

3+2=5=5^2=25

5+2=7=7^2=49

7+2=9=9^2=81

9+2=11=11^2=121

11+2=13=13^2=169

So ans is 169

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