5×-4y+8=0 ,7×+6y-9=0
Answers
Answer:
MRK BRAINLIET ND THANK ME PLLLLsssss
Step-by-step explanation:
5x-4y+8=0 be equation 1st
7x+6y-9=0 be equation 2nd
solve these two equations to find the intersection point of these two equation
5x-4y=-8 be equation 1st
7x+6y=9 be equation 2nd
multiply 1st equation by 3 and multilply 2nd equation by 2 to gey the coefficient of y equal i am using elimination method to solve x and y
5x(3) -4y(3) = -8×3
7x(2)+6y(2) = 9×2
15x-12y=-24 equation 3rd
14x+12y=18 equation 4th
add these two equation
15x+14x-12y+12y=-24+18
29x=-6
x=-6/29
substitute x=-6/29en equation 1st 5x-4y=-8
5(-6/29)+-4y=-8
4y=(30/29)-8
4y=(30-29×8)/29
4y=-202/29
2y=-101/29
y=-101/58
we get the value of x and y now on representing these two line on graph i put
these two lines intersect at point p point p is (-6/29,-101/58)
