√5+√5+√5+..........?
Answers
Answered by
3
let the total terms be,
"n"
Using sum to 'n' terms of A.P
Sn=n/2(2a+(n-1)d)
d=0
n/2x2a
=>an
therefore,
Sn=an
and.
a=√5
so,
sn=n√5
thanks!
Answered by
5
This is a theorem found in Ramanujams Notebook 4.
It is toooo difficult to prove.
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