Math, asked by shivaqu, 1 year ago

√5√5√5√5√5√5 is equal to ....answer is 5 to the power 63/64 .this only i need​

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pkkkkkkkkkkkkk: hlo mere saat Chat karogi meri gf banogi meri gf banogi meri gf

Answers

Answered by NeelamG
4

here 2 is for square root

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NeelamG: this answer will help u
NeelamG: shiva
NeelamG: qu
NeelamG: no i will not help u pkk
shivaqu: thanks neelam
shivaqu: can you elaborate second step
shivaqu: and why 2
shivaqu: root is equal to 1/2
NeelamG: it is 1 - (1/2^6)
NeelamG: it is general form for such type of questions
Answered by Mithalesh1602398
1

Answer:

The correct answer is 5^{\frac{63}{64}}

Step-by-step explanation:

Step 1: If all of the following are true, a radical is said to be in simplified radical form (or simply simplified form).

There cannot be no exponents in the radicand greater than the index.

There can be no exponents in the radicand that share a factor with the index.

Under a radical, there are no fractions.

$$\begin{aligned}& \sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5}}}}}} \\& \sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5}}}}}=\sqrt{5} \sqrt{\sqrt{5} \sqrt{\sqrt{5} \sqrt{5^{\frac{3}{4}}}}} \\& =\sqrt{5 \sqrt{5} \sqrt{\sqrt{5} \sqrt{\sqrt{5} \sqrt{5^{\frac{3}{4}}}}}}\end{aligned}$$

Step 2:Apply radical rule: $\sqrt[n]{a b}=\sqrt[n]{a} \sqrt[n]{b}, \quad$ assuming $a \geq 0, b \geq 0$

$$=\sqrt{5} \sqrt{\sqrt{5} \sqrt{\sqrt{5} \sqrt{\sqrt{5} \sqrt{5^{\frac{3}{4}}}}}}$$

$$\begin{aligned}& \sqrt{\sqrt{5} \sqrt{\sqrt{5} \sqrt{\sqrt{5} \sqrt{5^{\frac{3}{4}}}}}}=5^{\frac{31}{64}} \\& =\sqrt{5} \cdot 5^{\frac{31}{64}}\end{aligned}$$

Apply radical rule: $\sqrt{a}=a^{\frac{1}{2}}=$

$$\begin{aligned}& \sqrt{5}=5^{\frac{1}{2}} \\& =5^{\frac{1}{2}} \cdot 5^{\frac{31}{0^4}}\end{aligned}$$

Step 3:Apply exponent rule: $a^b \cdot a^c=a^{b+c}$

$$\begin{aligned}& 5^{\frac{1}{2}} \cdot 5^{\frac{31}{64}}=5^{\frac{1}{2}+\frac{31}{64}} \\& =5^{\frac{1}{2}}+\frac{31}{64}\end{aligned}$$

$$\begin{aligned}& \frac{1}{2}+\frac{31}{64}=\frac{63}{64} \\& =5^{\frac{63}{64}}\end{aligned}$$

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