Question

5
5. If x varies directly with 3y + 5 and y =3
when x = 10, then what is the value of y,
when x = 36?​

Answer 1

Answer:

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Step-by-step explanation:

x Varies directly with 3y+5

i.e., x=K(3y+5)

If y=53 when x=10

⟹10=K(3×53+5)

⟹10=K(59+5)

⟹10=K×534

⟹K=10×345=1725

∴x=1725(3y+5)

When x=35 then,

35=1725(3y+5)

⟹35×2517=3y+5

⟹5119=3y+5

⟹5119−5=3y

Answer 2

Answer:

120

Step-by-step explanation:

x = 10 (x1) then y = 3(y1 )

when x = 36 (x2) then y (y2) ?

Direct variation = x/y

= x1/y1 = x2/y2

10/3= 36/y2

10×36/3 = y2

120= y2