5.
52
6.
2067 Q.No. 8 HOW do you convert a galvanometer into a voltmeter?
2067 Q.No. 14 What is the ratio of maximum to minimum resistance when a wire is
stretched to double of its length?
2064 Q.No. 1 Ammeter are always connected in series in a electrical circuit, why?
WA
Answers
Explanation:
when connected as ammeter effective resistance of circuitR=r+99//1+2=r+0.99+2
current in circuit = R12=3⇒312=R⇒4=r+0.99+2⇒r=1.01Ω
consider the voltmeter circuit,
current in circuit = r+212=4A
voltage across 2 ohm resistance = 2+1212=8V
this is 4/5th of full scale reading.
Therefore full scale reading of voltmeter= 458=10V
current passing through the voltmeter= 200+224≈0.04A
this is 4/5th of maximum current allowed in the galvanometer when used as voltmeter.
therefore ,
maximum current allowed in galvanometer when used as voltmeter= 450.04=0.05A
therefore full scale reading of galvanometer is 0.05A . Therefore x=5
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