5√5xsquare +30x +8√5 find the zeroes of the following polynomial:
Virat360:
Remember this is square
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Answered by
1
Answer:
Step-by-step explanation:
5√5x² + 30x + 8√5
splitting the middle term
= 5√5x² + 20x + 10x + 8√5
= 5√5x² + 4 × 5x + (2√5 ) × √5 x + 2√5 × 4
= 5x ( √5x + 4 ) + ( 2√5 ) [ √5x + 4 ]
= ( √5x + 4 ) ( 5x + 2√5 )
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Answered by
15
5√5xsquare +30x +8√5, find the zeroes of the following polynomial.
Good question,
Here is your answer!
= 5√5x² + 30x + 8√5
= 5√5x² + 20x + 10x + 8√5
= 5x(√5x + 4) + 2√5(√5x + 4)
= (5x + 2√5) (√5x + 4)
=) (5x + 2√5) (√5x + 4) = 0
=) x = ( - 2√5)/5 or x = - 4/√5
x = (-2/√5) or (-4/√5)
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