Question

5/6-2/3 solve3/4+5/7​

Answer 1

Answer:

$a) \: \frac{1}{6}$

$b) \: 1 \frac{13}{28}$

Step-by-step explanation:

a) Find the LCM of their denominators

2 | 6, 3

3 | 3, 3

1, 1

LCM of 6 and 3 = 2 × 3

= 6

$\frac{5 \times 1}{6 \times 1} = \frac{5}{6}$

$\frac{2 \times 2}{3 \times 2} = \frac{4}{6}$

$\frac{5}{6} - \frac{4}{6} = \frac{5 - 4}{6} = \frac{1}{6}$

b) Find the LCM of their denominators

2 | 4, 7

2 | 2, 7

7 | 1, 7

1, 1

LCM of 4 and 7 = 2 × 2 × 7

= 28

$\frac{3 \times 7}{4 \times 7} = \frac{21}{28}$

$\frac{5 \times 4}{7 \times 4} = \frac{20}{28}$

$\frac{21}{28} + \frac{20}{28} = \frac{21 + 20}{28} = \frac{41}{28}$

Convert improper fraction into mixed fraction

1 => Quotient

28 | 41

- 28

13 => Remainder

$q \frac{r}{d} = 1 \frac{13}{28}$