5 6. An organic substance containing carbon ,hydrogen, and oxygen gave the percentage composition C=40.687%, H=5.085%,0=54.228% and the molecular mass of the compound is 118 calculate the empirical and molecular formula of compound
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Therefore, Percentage of O = 100 - (40.687+5.085) = 54.228%. Step I: To calculate the empirical formula of the compound. Since, ration of C : H : O = 2 :3 :2. ∴ An empirical formula is C2H3O2.
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