Question

5.6 g of metal oxide in a reaction produces 10 g of its carbonate, the equivalent weight of the metal is​

Answer 1

Answer:

10/5.6 is equal to 1.7 is the right answer

Answer 2

Answer:

20

Explanation:

5.6g of metal forms 10g of its carbonate

the amount of carbondioxide present in 10g of carbonate = 10g -5.6g

=4.4g

Thus, 5.6g of metal combines with 4.4g of Co2

The equivalent weight of metal carbonate is = 10×22/4.4

=50g

equivalent weight of carbonate ion = CO3/2 = 60/2 =30

●EQUIVALENT MASS OF METAL IS =50-30 = 20g