Question

5.
.
6.
In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of
minor arc of the chord.
If in two circles, arcs of the same length subtend angles 60° and 75° at the
centre, find the ratio of their radii.
Tind the angle in radian through which a nendulum swings if its length is 75 cm​

Answer 1

where is the fifth question?

Answer 2

Step-by-step explanation:

diameter of the circle= 40 cm

radius(r) of the circle = 40/2 = 20cm

let AB be a chord ( length= 20 cm) of the circle.

In ∆OAB,OA= OB = Radius of circle= 20 cm

Also, AB=20 cm

Thus, ∆OAB is an equilateral triangle.

theta = 60° = π/3 radian

we know that in a circle of radius r, unit,if an arc of length 1 unit subtends an angle theta radian at the center, then theta = 1/r

π/3= arc AB /20 = arc AB = 20/3 π cm