Question

5.6 L of oxygen at STP contains -? atom
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Answer 1

Answer:

22.4 liter contain 6.022×10^23 atoms

5.6 liter will contain

=5.6×6.022×10^23/22.4

=6.022×10^23/4

=1.5×10^23 atoms

Answer 2

Answer:

22.4 L of Oxygen weighs 32g at STP

So 5.6 L of Oxygen will weigh

= 32/22.4 *5.6

i.e. equal to =8g

Thus it will weigh 8g

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