Question

5.6 liters of oxygen at ntp is equivalent to

Answer 1

$5.6l \: of \: o2 \: is \: equal \: to$

$5.6 \div 22.4 = mole$

$2.5 \times {10}^{ - 1 \:} mole$

therefore 5.6 L of oxygen is equal to 2.5x10^-1 mole

Answer 2

Answer: The given volume of oxygen gas is equal to 0.25 L

Explanation:

At NTP, the conditions are:

1 mole of gas occupies 22.4 L of volume

We are given:

Volume of oxygen gas = 5.6 L

As, 22.4 L of volume is occupied by 1 mole of a gas

So, 5.6 L of volume will be occupies by $\frac{1mol}{22.4L}\times 5.6L=0.25mol$ of gas

Hence, the given volume of oxygen gas is equal to 0.25 L