5.6 litre of water contains at STP how many atoms
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One mole of a gas contains 6.023 x 10^23 constituent particles of the gas and occupies 22.4 L volume. Therefore, 5.6 L is occupied by 0.25 moles of a gas, which will therefore contain 0.25 x 6.023 x 10^23 particles. 1.50575 * 10^23 molecules of Oxygen gas in 5.6 L.Oct 16, 2017
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22.4 litre contains 6.022×10^23×3 atoms
5.6 litre contains,
=6.022×10^23×3×5.6/22.4
=4.5165×10^23
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