Chemistry, asked by fatimazoha003, 8 months ago

5.61 g of KOH is dissolved in 200ml of water in a styrofoam calorimetre. The temperature rise is 9 degree Celsius. Calculate the
a)the number of joules absorbed by the water due to the dissolving of KOH.
b) the number of moles of KOH dissolved in the reaction
c) the heat of the reaction in kJ/mol for the dissolving of potassium hydroxide in water

PLEASE HELP ME!!

Answers

Answered by Anonymous
5

5.61 g of KOH is dissolved in 200ml of water in a styrofoam calorimetre. The temperature rise is 9 degree Celsius. Calculate the

a)the number of joules absorbed by the water due to the dissolving of KOH.

b) the number of moles of KOH dissolved in the reaction

c) the heat of the reaction in kJ/mol for the dissolving of potassium hydroxide in water

5.61 g of KOH is dissolved in 200ml of water in a styrofoam calorimetre. The temperature rise is 9 degree Celsius. Calculate the

a)the number of joules absorbed by the water due to the dissolving of KOH.

b) the number of moles of KOH dissolved in the reaction

c) the heat of the reaction in kJ/mol for the dissolving of potassium hydroxide in water

5.61 g of KOH is dissolved in 200ml of water in a styrofoam calorimetre. The temperature rise is 9 degree Celsius. Calculate the

a)the number of joules absorbed by the water due to the dissolving of KOH.

b) the number of moles of KOH dissolved in the reaction

c) the heat of the reaction in kJ/mol for the dissolving of potassium hydroxide in water

PLEASE HELP ME!!

PLEASE HELP ME!!

PLEASE HELP ME!!

Answered by murtajashaikh26
0

Explanation:

[KOH]=[K

+

]=[OH

]=

56×200

0.561×1000

=0.050M

[H

+

]=

OH

]

K

w

=

0.05

10

−14

=2.0×10

−13

pH=−log[H

+

]=−log(2.0×10

−13

)=12.699

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