Question

5 (6x + 1) = 3 (-8 + x) + 2​

Answer 1

• As per the data given in the question, we have to find the value of the expression.

            Given data:- $5(6x+1)=3(-8+x)+2.$

             To find:- the value of the expression.

             Solution:-  

• Here, we will use the below following steps to find a solution using the transposition method:

• Step 1:- we will Identify the variables and constants in the given simple equation.

• Step -then we Simplify the equation in LHS and RHS.

• Step 3:- Transpose or shift the term on the other side to solve the equation further simplest.

• Step 4:- Simplify the equation using arithmetic operation as required that is mentioned in rule 1 or rule 2 of linear equations.

• Step 5:- Then the result will be the solution for the given linear equation. By using the transposition method. we get,

            $5(6x+1)=3(-8+x)+2\\30x+5=-24+3x+2\\30x+5=-22+3x\\30x-3x=-22-5\\27x=-27\\x=\frac{-27}{27} \\x=-1.$

    Hence we will get the value $x=-1.$

         

Answer 2

Given equation is ,

$5 (6x + 1) = 3 (-8 + x) + 2$

Here we have to find the value of $x$

In order to find the value of $x$ we have to solve the given equation.

$30x+5=-24+3x+2$

Transpose all the $x$ terms to LHS and all the constant terms to RHS .

$30x-3x=-5-24+2$

$27x=-29+2$

$27x=-27$

$x=-1$

Therefore, the value of $x$ is $-1$.