5/7= ...../ 28=35/.....=...../3 5, Using the property a/b=ak/bk fill in the blank substituting proper numbers.
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Given 5/7 = ?/28 = 35/? = ?/35
[ By a/b = ak/bk property ]
i ) 5/7 = (5×4)/(7×4) = 20/28
ii ) 5/7 = ( 5×7 )/(7×7) = 35/49
iii ) 5/7 = ( 5×5 )/(7×5) = 25/35
Therefore ,
5/7 = 20/28 = 35/49 = 25/35
••••
[ By a/b = ak/bk property ]
i ) 5/7 = (5×4)/(7×4) = 20/28
ii ) 5/7 = ( 5×7 )/(7×7) = 35/49
iii ) 5/7 = ( 5×5 )/(7×5) = 25/35
Therefore ,
5/7 = 20/28 = 35/49 = 25/35
••••
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