Math, asked by sreevishnu77, 1 year ago

(5/7)^-3×(5/7)^-11=(5/7)^7×^x

Answers

Answered by webstar1
0
(5/7)^-3×(5/7)^-11=(5/7)^7×^x

(5/7)^-3+(-11) = (5/7)^7*^x

(5/7)^-3-11. = (5/7)^7x

(5/7)^-14. = (5/7) ^7*-2

(5/7)^-14. = (5/7)^-14

then , x = -2

hope it helps u


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