Question

5;7= 37 8;4=20 10;6=34 6;4=?

Answer 1

Given data :  

Sets are

5;7=37    8;4=20     10;6=34

To find :  

The missing number in 6;4 = ?  

Solution:

Logic applied behind :

Let A, B, C are the three numbers in the given set respectively.

Then, apply C = ( A² - B²) / | A - B |

5;7=37, Here C = 37 :

A = 5, B = 7

Then, ( 5² + 7² ) / | 5 - 7 |

        = (25 + 49) / |-2|

        = 74/2

        = 37         [=C]

8;4=20, Here C = 20 :

A = 8, B = 4

Then, ( 8² + 4² ) / | 8 - 4 |

        = (64 + 16) / |4|

        = 80/4

        = 20         [=C]

10;6=34, Here C = 34 :

A = 10, B = 6

Then, ( 10² + 6² ) / | 10 - 6 |

        = (100 + 36) / |4|

        = 136/4

        = 34         [=C]

6;4=?, Here C = ? :

A = 6, B = 4

So, C = ( 6² + 4² ) / | 6 - 4 |

         = (36 + 16) / |2|

         = 52/2

         = 26         [=C]

So, 26 is the answer.

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