Math, asked by kumarrohan9992, 9 months ago

5 7 (37) 8 4(20) 10 6(34) 6 4(?) Find missing number

Answers

Answered by poojan
0

Given data :  

Sets are

5 7 (37)   ;   8 4 (20)   ;   10 6 (34)

To find :  

The missing number in 6 4 (?)  

Solution:

Logic applied behind :

Let A, B, C are the three numbers in the given set respectively.

Then, apply C = ( A² - B²) / | A - B |

5 7 (37), Here C = 37 :

A = 5, B = 7

Then, ( 5² + 7² ) / | 5 - 7 |

        = (25 + 49) / |-2|

        = 74/2

        = 37         [=C]

8 4 (20), Here C = 20 :

A = 8, B = 4

Then, ( 8² + 4² ) / | 8 - 4 |

        = (64 + 16) / |4|

        = 80/4

        = 20         [=C]

10 6 (34), Here C = 34 :

A = 10, B = 6

Then, ( 10² + 6² ) / | 10 - 6 |

        = (100 + 36) / |4|

        = 136/4

        = 34         [=C]

6 4 (?), Here C = ? :

A = 6, B = 4

So, C = ( 6² + 4² ) / | 6 - 4 |

         = (36 + 16) / |2|

         = 52/2

         = 26         [=C]

So, 26 is the answer.

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Answered by rohitkumargupta
1

Answer:

(?)= (26)

Step-by-step explanation:

HELLO DEAR,

Given : 57(37), 84(20) , 106 (34), 64(?).

It is logical base question.

After making some logic you find ,

( ) = (A^2 + B^2)/ lA-Bl. .................i)

where A= (5,8,10,6)

B=( 7,4,6,4).

Now ,(1). (37) = (5^2 + 7^2)/ l5-7l

= (25+49)/ l-2l

= 74/2

(37) = 37.

(2). (20) = (8^2+4^2)/l8-4l

= (64+16)/4

= 80/4

(20)=20

(3). (34) = (10^2+6^2)/l10-6l

= (100+36)/ l4l

=136/4

(34) = 34

(4). (?) = (6^2 + 4^2)/ l6-4l

= (36+16)/2

= 52/2

(?) = 26. Answer.

I HOPE IT HELP YOU DEAR,

THANKS.

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