5;7; 37 8;4; 20 6;4;? 6;10; 34
Answers
Given data :
Sets are
5 7 (37) ; 8 4 (20) ; 10 6 (34)
To find :
The missing number in 6 4 (?)
Solution:
Logic applied behind :
Let A, B, C are the three numbers in the given set respectively.
Then, apply C = ( A² - B²) / | A - B |
5 7 (37), Here C = 37 :
A = 5, B = 7
Then, ( 5² + 7² ) / | 5 - 7 |
= (25 + 49) / |-2|
= 74/2
= 37 [=C]
8 4 (20), Here C = 20 :
A = 8, B = 4
Then, ( 8² + 4² ) / | 8 - 4 |
= (64 + 16) / |4|
= 80/4
= 20 [=C]
10 6 (34), Here C = 34 :
A = 10, B = 6
Then, ( 10² + 6² ) / | 10 - 6 |
= (100 + 36) / |4|
= 136/4
= 34 [=C]
6 4 (?), Here C = ? :
A = 6, B = 4
So, C = ( 6² + 4² ) / | 6 - 4 |
= (36 + 16) / |2|
= 52/2
= 26 [=C]
So, 26 is the answer.
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Answer: