Question

(5/7)square÷(5/7)^3x+1=(5/7)^4​

Answer 1

Answer:

answer is x = -1

Step-by-step explanation:

(5/7)² ÷ (5/7)^(3x+1) = (5/4)^4

(5/7)² × (5/7)^-(3x+1) = (5/7)^4

(5/7)^[2-(3x+1)] = (5/7)^4

base is same on both side

so , compairing of power

2 - (3x + 1) = 4

2 - 3x - 1 = 4

1 - 3x = 4

-3x = 4 - 1

-3x = 3

-x = 3/3

-x = 1

x = -1