Question

5.75 +- 0.02 g of a substance occupies 1.5 +- 0.1cm ^3 express the density of the substance in terms of % error
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Answer 1

density=mass/volume

m=5.75    Δm=0.02

v=1.5        Δv=0.1

d=m/v

  =5.75/1.5

  =3.83

By error analysis

d/Δd=m/Δm+v/Δv

putting the values Δd=0.01

∴d=8.83 $\frac{+}{}$ 0.01 g/cm³

Answer 2

As we know that,

Given:

Mass of a substance = $5.75$

Δ$m=0.02$

Find out:

The density of the substance in terms of % error

Let us:

$Density =$ $\frac{mass}{volume}$

so,

$m=5.75$

Δ$m=0.02$

$v=1.5$      

Δ$v=0.1$

then,

d=$\frac{m}{v}$

  =$\frac{5.75}{1.5}$

$=3.83$

Now by error analysis d/Δd=m/Δm+v/Δv

putting the values Δd=0.01

d=8.83 ± 0.01g/cm³