Question

5. 75 g of water decreases from 45°C to 25°C.
If the specific heat of water is 1 Cal/gm°C,
the heat energy released is​

Answer 1

Answer:

heat energy = m × c × delta t

delta t = rise or decrease in temp

c = specific hear

m = mass

decreae in temp = 20°C

so , heat energy = 75 × 1 × 20

heat energy = 1500 j