Math, asked by markandey192575, 3 months ago

5-8-6/6 simplyfy this​

Answers

Answered by sonamsharmanamo
0

Answer:

Steps:

1. draw base AB=4cm

2. with A as center, with a scale of 5cm as radius draw an arc and with B as center, with a scale of 6cm as radius draw an arc.

3. let C be the point of intersection of the above 2 lines.

4. draw a ray AX making an acute angle with line AB on the opposite side if the vertex C.  

5. mark 3 points A1,A2,A3 such tha A1A2=A2A3=A3A1

6. join A3B and draw a parallel line B  

A2

7. draw a line parallel to BC  to intersect AC at C  

 

Thus AB  

C  

 is a required triangle.

Justification;

By construction,

AB

AB  

 

​  

=  

AA3

AA2

​  

=  

3

2

​  

 

also B  

C  

∥BC

∴∠AB  

C  

=∠ABC

In △AB  

C  

,△ABC

∠A=∠A

∠AB  

C  

=∠ABC

△AB  

C  

∼△ABC

⇒  

AB

AB  

 

​  

=  

AC

AC  

 

​  

=  

BC

B  

C  

 

​  

 

∴  

AB

AB  

 

​  

=  

AC

AC  

 

​  

=  

BC

B  

C  

 

​  

=  

3

2

Step-by-step explanation:

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