Question

5-8
. If the following three equations hold
simultaneously for x and y, find p.

3x - 2y = 6, x/3- y/6 =1/2
x - py = 6.
​

Answer 1

Answer:

3x−2y=6−−−eqn(1)

3

x

−

6

y

=

2

1

Multiplying with LCM of 3 and 6 on both sides.

LCM of 3 and 6 is 6

2x−y=3−−−eqn(2)

Multiplying eqn(2) with 2

4x−2y=6−−−eqn(3)

then subtracting eqn(3) from eqn(1) we get x=0.

Substituting x=0 in eqn(1) we get y=−3

Substituting x=0 and y=−3 in x−py=6

⇒ 0−p×(−3)=6

p=2

Answer 2

Answer:

Answer is in the photograph