5-8
. If the following three equations hold
simultaneously for x and y, find p.
3x - 2y = 6, x/3- y/6 =1/2
x - py = 6.
Answers
Answered by
1
Answer:
3x−2y=6−−−eqn(1)
3
x
−
6
y
=
2
1
Multiplying with LCM of 3 and 6 on both sides.
LCM of 3 and 6 is 6
2x−y=3−−−eqn(2)
Multiplying eqn(2) with 2
4x−2y=6−−−eqn(3)
then subtracting eqn(3) from eqn(1) we get x=0.
Substituting x=0 in eqn(1) we get y=−3
Substituting x=0 and y=−3 in x−py=6
⇒ 0−p×(−3)=6
p=2
Answered by
1
Answer:
Answer is in the photograph
Attachments:
Similar questions