Question

5.85 gram of nacl is completely electrolysed volume of cl2 obtained at stp??​

Answer 1

Answer:

Water is reduced at the cathode:

H

2

O+e→

2

1

H

2

+OH

−

So we need 1 mole of electrons to produce 1 mole of OH- ions.

The charge on 1 mole of electrons is given by the Faraday Constant F. This has the value of 9.65×10

4

C/mol

Electric current I is the rate of flow of charge:

I=

t

Q

Q=1×60×60=3600 C

To find the number of moles of electrons this represents we divide by the charge on 1 mole of electrons:

No. moles electrons =

9.65×10

4

3600

= 0.0573

Concentration = no. moles/volume of solution so:

OH

−

=

1

0.573

=0.573 M

We know that [H

+

][OH

−

]=10

−14

mol

2

l

−2

[H

+

]=

0.0573

10

−14

=1.745×10

−13

pH = 12.76