CBSE BOARD XII, asked by asdfg7049, 1 year ago

5,9,18,43,92,213,382,?​

Answers

Answered by jethaprajapat213
1

Answer:

Each number is added woth the square of infractional number.such as 2 3 5 7 11 13 17 so next number will be

382+17x17=671 .

Answered by Hansika4871
1

Given:

A series of numbers 5,9,18,43,92,213,382,?​  

To Find:

The missing number in the series is?  

Solution:  

The given problem can be solved by developing a common logic between every term.  

1. The given series is 5,9,18,43,92,213,382,?​.  

2. The second term in the series is obtained as,  

=> Second term = 5 + 2² = 9,  

3. The third term of the series is obtained as,  

=>Third term = 9 + 3² = 18, ( next prime number after 2 is 3 )

4. The fourth term of the series is obtained as,  

=>Fourth term =  18 + 5² = 43, ( next prime number after 3 is 5 )

5. The fifth term of the series is obtained as,  

=>Fifth term = 43 + 7² = 92, ( next prime number after 5 is 7 )

6. The sixth term of the series is obtained as,  

=>Sixth term = 92 + 11² = 213, ( next prime number after 7 is 11 )

7. The seventh term of the series is obtained as,

=> Seventh term = 213 + 13² = 382, ( next prime number after 11 is 13 )

8. The next term of the series can be obtained using the same logic,

=> Eighth term = 382 + 17² = 382 + 289 = 671. ( next prime number after 13 is 17 ).

Therefore, the next term in the series is 671.

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