Question

(5/9)-²×(3/5)-³×(3/5)⁰

evaluate the above question☝️

the two minus signs are with the two powers -2 and -3 ​

Answer 1

Step-by-step explanation:

whenever there is minus sign with power,the fraction inverses...and whenever there is a 0 power the fraction becomes 1.

Answer 2

Answer:

The answer is 15.

Given:

$(\frac{5}{9} )^{-2}$ × $(\frac{3}{5} )^{-3}$ × $(\frac{3}{5} )^{0}$

Step-by-step explanation:

we know that,

$a^{0} = 1$,

therefore,

$(\frac{3}{5} )^{0} = 1$

Also,

$(\frac{5}{9} )^{-2}$ can be written as,

$\frac{(5)^{-2} }{(3^{2} )^{-2} } = \frac{(5)^{-2} }{(3)^{-4} }$

$(\frac{3}{5} )^{-3}$ can be written as,

$= \frac{(3)^{-3} }{(5)^{-3} }$

Hence,

$(\frac{5}{9} )^{-2}$ × $(\frac{3}{5} )^{-3}$ × $(\frac{3}{5} )^{0}$ = $\frac{(5)^{-2} }{(3)^{-4} }$ × $\frac{(3)^{-3} }{(5)^{-3} }$ × $1$

⇒ $\frac{(5)^{-2} }{(5)^{-3} }$ × $\frac{(3)^{-3} }{(3)^{-4} }$

{ $\frac{(a)^{n} }{(a)^{m} } = a^{n-m}$}

⇒ $5^{[-2 - (-3)] }$ × $3^{[-3 - (-4)]}$

⇒ $5^{[-2 + 3)] }$ × $3^{[-3 + 4)]}$

⇒ 5 × 3

⇒ 15

hence, the answer is 15.

#SPJ2