Question

(5/9)^4×(5/9)^-8=(5/9) ^2x-1 (find the value of x)​

Answer 1

$( { \frac{5}{9} })^{4} \times ( { \frac{5}{9} })^{ - 8} = ( { \frac{5}{9} })^{2x - 1} \\ base \: is \: same \: so \: equate \: the \: powers \\ 4 \times ( - 8) = 2x - 1 \\ - 32 = 2x - 1 \\ 2x = - 32 + 1 \\ 2x = - 31 \\ x = \frac{ - 31}{2}$

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