Question

(-5/9) raised to power -2 x (-3/5) raised to power -3 x (3/5) raised to power -0
Solve using laws of exponents

Answer 1

Answer:

$= > - 15$

Step-by-step explanation:

$( - \frac{5}{9} ) {}^{ - 2} \times ( - \frac{3}{5} ) {}^{ - 3} \times (\frac{3}{5} ) {}^{ - 0}$

$= ( \frac{9}{5} ) {}^{2} \times ( - \frac{5}{3} ) {}^{3} \times 1$

$= \frac{9}{5 } \times \frac{9}{5} \times ( - \frac{5}{3} ) \times ( - \frac{5}{3} ) \times ( - \frac{5}{3} )$

$= 3 \times ( - 5) \\ = > (- 15)$