Physics, asked by swati1246, 1 year ago

5-9.
Tune Y = TUm/seca
A toy plane P starts flying from point A along a straig
with zero initial velocity a
vertically upwards with initial velocity 'u'. Ball touche
nitial velocity and acceleration 2 m/s2 as shown. At the same
plane s journey when it is vertically above the man. 's' is the distance
the contact of ball with the plane, acceleration of plane incre
le plane, acceleration of plane increases to 4 m/s. Find:
along a straight horizontal line 20 m above ground level starting
2 m/s? as shown. At the same instant, a man P throws a ball
ball touches (coming to rest) the base of the plane at point B of
ve the man. 's' is the distance of point B from point A. Just after
A
>B
20 m
(i) Initial velocity 'u' of ball.
(ii) Distance 's'.
stance between man and plane when the man catches the ball back. (g = 10 m/s) (Neglect the
height of man)

Answers

Answered by abuumar
3

G bhai aap bhai dekhiye 29th the


swati1246: can you explain this to me
Answered by sankalpguptajnv
1

Explanation:

for ball v=0 going upward g=-10 m/s2

v^2=u^2+2as

from this u = 20m/s

time taken by ball is equal to

v =u+at

t=2sec

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