5.
a) 0.3 ms 5,0.6 ms b) 0.67
If a scooter acquires a velocity of 36 kmph in 10 s just after its start, then the acceleration of the scou
IC
a) 3 ms^-2
b) 2 ms^-2
c) 1 ms^-2
d) 0.5 ms^-2
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Given :
u (initial velocity) = 0 (rest) , v (final velocity) = 36 km/ hr = 36 × (1000/3600)
v = 36× 5/18 = 10 m/s. , t = 10s
From first equation of motion , v = u + at
10 = 0 + a ×10
10 = 10a
a = 10/10
a = 1 m/s²
acceleration of the scooter = 1 m/s²
Hence, the acceleration of the scooter is 1 m/s².
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