Question

5.
A = {-1, 1}
find AX AXA​

Answer 1

Step-by-step explanation:

A×A×A first do for A×A

A×A={-1,1}×{-1,1}={(-1,-1)(-1,1)(1,-1)(1,1)}

thn consider whole equation as 1

thn do fr A×A×A={-1,1}×{(-1,-1)(-1,1)(1,-1)(1,1)}

thn answer is {(-1-1-1),(-1-1,1),(-1,1,-1)(-1,1,1)(1,-1,-1)(1,-1,1)(1,1,-1)(1,1,1)}