Question

5.
(a) 115 and 140
Find the H.C.F. of the following by prime factorization method.
(a) 91 and 1638
(b) 352 and 3168
(c) 81 and 729
u prime factorization method.​

Answer 1

Answer:

(a) 115 and 140 = 5

115/5 = 23 , 140/5 = 28  

23 is a prime number.

So HCF is 5

(b) 91 and 1638

91/7 = 13 ,  1638/7 = 234

13 is a prime number.

So HCF is 7

(c) 352 and 3168

352/2 = 176 , 3168/2 = 1584

176/2 = 88  , 1584/2 = 792

88/2 = 44 ,  792/2 = 396

44/2 = 22 , 396/2 = 198

22/2 = 11 , 198/2 = 99

11/11 = 1 , 99/11 = 9

So HCF is 2 x 2 x 2 x 2 x 2 x 11 = 352

(d) 81 and 729

81/ 3 = 27 , 729/3 = 243

27/3 = 9 , 243/3 = 81

9/3 = 3 , 81/3 = 27

3/3 = 1 , 27/3 = 9

So HCF is 3 x 3 x 3 x 3 = 81

HOPE IT HELPS!!!!