5(a+2)-3(a-1)=3
solve it please
Answers
How to solve your problem
Topics: Precalculus, Matrix
5
(
+
2
)
−
3
(
−
1
)
=
3
5(a+2)-3(a-1)=3
5(a+2)−3(a−1)=3
Solve
1
Distribute
5
(
+
2
)
−
3
(
−
1
)
=
3
{\color{#c92786}{5(a+2)}}-3(a-1)=3
5(a+2)−3(a−1)=3
5
+
1
0
−
3
(
−
1
)
=
3
{\color{#c92786}{5a+10}}-3(a-1)=3
5a+10−3(a−1)=3
2
Distribute
5
+
1
0
−
3
(
−
1
)
=
3
5a+10{\color{#c92786}{-3(a-1)}}=3
5a+10−3(a−1)=3
5
+
1
0
−
3
+
3
=
3
5a+10{\color{#c92786}{-3a+3}}=3
5a+10−3a+3=3
3
Add the numbers
5
+
1
0
−
3
+
3
=
3
5a+{\color{#c92786}{10}}-3a+{\color{#c92786}{3}}=3
5a+10−3a+3=3
5
+
1
3
−
3
=
3
5a+{\color{#c92786}{13}}-3a=3
5a+13−3a=3
4
Combine like terms
5
+
1
3
−
3
=
3
{\color{#c92786}{5a}}+13{\color{#c92786}{-3a}}=3
5a+13−3a=3
2
+
1
3
=
3
{\color{#c92786}{2a}}+13=3
2a+13=3
5
Subtract
1
3
13
13
from both sides of the equation
2
+
1
3
=
3
2a+13=3
2a+13=3
2
+
1
3
−
1
3
=
3
−
1
3
2a+13{\color{#c92786}{-13}}=3{\color{#c92786}{-13}}
2a+13−13=3−13
6
Simplify
Subtract the numbers
Subtract the numbers
2
=
−
1
0
2a=-10
2a=−10
7
Divide both sides of the equation by the same term
2
=
−
1
0
2a=-10
2a=−10
2
2
=
−
1
0
2
\frac{2a}{{\color{#c92786}{2}}}=\frac{-10}{{\color{#c92786}{2}}}
22a=2−10
8
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
−
5
answer a = -5