Question

5. A 200W bulb emits monochromatic light of
wavelength 600nm.Calculate the number of
photons emitted per second by the bulb​

Answer 1

Explanation:

P=nE/t-----(1)

w.k.t P=200W;wavelength=600nm;t=1 sec

E=hc/wavelength

E=6.626×10^-34×3×10^8 / 6×10^-7

E= 3.313×10^-19 J

Substitute this in (1),we get

200=n×3.313×10^-19/ 1

n=6.04×10^20 photons