Question

5. A 40 kg flywheel in the form of a uniform circular
disc 200 cm. in diameter is making 120
revolutions/minute. Calculate angular momentum.
Moment of inertia of disc=(1/2) mass x (radius).
[Ans. 251-4 kg mas-​

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\red{\boxed{\sf Angular\: Momentum(L)=251.4\:kg.{m}^{2}/s}}$

$\huge\underline\blue{\sf Answer:}$

$\large\underline\pink{\sf Given: }$

• Mass of flywheel (m) = 40kg

• Diameter = 200cm =2m

• Radius (r) = 1m

• $\large{\omega}$=120 rev/m

$\large\underline\pink{\sf To\:Find: }$

• Angular Momentum (L) = ?

━━━━━━━━━━━━━━━━━━━━━━━━━

$\large{♡}$${\boxed{\sf Angular\: Momentum (L)=Inertia (I)×\omega}}$

$\large\implies{\sf Inertia(I)={\frac{M{R}^{2}}{2}}}$

$\large\implies{\sf {\frac{40×{1}^{2}}{2}} }$

$\large{\boxed{\sf I=20kg-{m}^{2}}}$

______________________________________

$\omega$=120 rev/m

Convert it into rad/s

$\large{\sf 120×{\frac{2π}{60}} }$

$\large{\boxed{\sf \omega =4π }}$

On putting its value in the Formula :

$\large\implies{\sf L=20×4π }$

$\large\implies{\sf 80π}$

$\large\implies{\sf 80×3.14 }$

$\large\implies{\sf 251.4\:kg.{m}^{2}/s }$

$\huge\red{♡}$$\red{\boxed{\sf Angular\: Momentum(L)=251.4\:kg.{m}^{2}/s}}$

Answer 2

Answer:

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Explanation:

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