5 A 5.0 g sample of dry ice (solid carbon dioxide) turned into 2400 cm3 of carbon dioxide gas at rtp. What was the percentage purity of the dry ice? (Mr of CO2 5 44.)
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Dry ice is solid carbon dioxide. A 0.05 g sample of dry ice is placed in an evacuated 4.6L vessel at 30
0
C. Calculate the pressure inside the vessel after all the dry ice has been converted to CO
2
gas.
answer
PV=nRT
P=
V
nRT
, we know that R=0.0821 L−atm/k−mol
Given T=30
o
C⇒30+273=303 k
V=4.6 L
n=
44.01 g CO
2
1 mol CO
2
=
44.01
0.059
=0.00113 mol CO
2
∴ P=
V
nRT
=
4.6
0.00113×0.0821×303
=
4.6
0.0281
=0.0061087=0.00612
∴ the closest ans is (D) 6.14×10
−3
atm
Hence, the correct option is D
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