Question

5. A 50 kg carte experiencing a 100N force with the direction 53 degree above horizontal, is moved over a horizontal rough surface through a distance of 5m. The coefficient of kinetic friction between the block and the horizontal surface is 0.5 then how much of work is done by the force?

Answer 1

Answer:

Correct option is

B

5 m/s

2

In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)

f=μN=μmg=0.5×10×10=50N

So, net force acting on the block in horizontal direction = 100 N-50 N = 50 N

acceleration of the block = Net force / mass of block = 50 N/10 kg = 5 ms

−2