Question

5. (a) A bus accelerates uniformly from 18 km/hr to 36 km/hr in 5sec.
Calculate (i) the acceleration (ii) the distance covered
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Answer 1

Answer:

$\bigstar{\bold{Acceleration\:=\:1\:m/s^{2} }}$

$\bigstar{\bold{Distance\:=\:37.5\:m}}$

Step-by-step explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Initial velocity (u) = 18 km/hr = 5 m/s
• Final velocity (v) = 36 km/hr = 10 m/s
• Time taken (t) = 5 s

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Acceleration (a)
• Distance (s)

$\Large{\underline{\underline{\bf{Solution:}}}}$

Acceleration:

→ Acceleration is given by the equation

  a = (v - u)/t

→ Substituting the given datas we get,

  a = (10 - 5)/5

  a = 1 m/s²

$\boxed{\bold{Acceleration\:=\:1\:m/s^{2} }}$

Distance covered:

→ By the third equation of motion,

 v² - u² = 2as

→ Substituting the datas we get,

  10²- 5² = 2 × 1 × s

(100 - 25)/2 =s

s = 37.5 m

$\boxed{\bold{Distance\:=\:37.5\:m}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ The three equations of motion are:

• v = u + at
• s = ut + 1/2 × a × t²
• v² - u² = 2as