5. A bag contains 3 red balls and 8 blue balls.
The probability of drawing red ball farem bag is -
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12th
Maths
Probability
Bayes Theorem
A bag contains three red ba...
MATHS
A bag contains three red balls and two blue balls. We remove successively, and with replacement, two balls and observe their colour. What is the probability of "to extract a red ball and a blue one, without taking into account the order"?
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ANSWER
Given:
Total number of balls in a bag = 3 red balls + 2 blue balls = 5
Let's consider the events: R= "to remove a red ball", A=R'= "to remove a blue ball.
Our sample space is: (RR, RA, AR, AA}, and the events that we are interested in are RA and AR.
We represent our problem in a tree as shown in the figure
Using the law of total probability,
P(S)=P(R)×P(A/R)+P(A)×P(R/A)=
5
3
×
5
2
+
5
2
×
5
3
=
25
12
is the required probability.
Answer:
The probablity is 8/11
As red ball are 8
And total number of balls is 8+3=11