Question

5. A battery of emf 80 V internal resistance 2 ohm is to be charged from 200 V mains. What is the value of series resistance for a charging current of 5A ?

(A) 11 ohm (B) 22 ohm (C) 33 ohm (D) 44 ohm​

Answer 1

Answer:

B) 22Ω

Explanation:

given:-

E = 80V

I = 5A

r = 2Ω

V = 200V

v = V - E = 200-80 = 120

v = I(R+r)

R+r = v/I

R = v/I - r

R = 120/5 - 2 = 24-2 = 22Ω