Physics, asked by vaibhavkawal, 2 months ago

5. A body goes round the circumference of a circle of radius 2 m with an
angular velocity of 2 rad/s. Its centripetal acceleration is
O 3 m/s2
O 1.5 m/s2
O 6 m/s2
O 12 m/s2

Answers

Answered by hardikmalik775
8

Answer:

Explanation:

R=2m.  w=2rad/s. Centripital accerlation = ?     C= v2/r.   V=rw ,2.2=4   c=4.4/2=8rad/s    

                                                                                                                                 

Answered by nirman95
3

Given:

A body goes round the circumference of a circle of radius 2 m with an angular velocity of 2 rad/s.

To find:

Centripetal acceleration?

Calculation:

  • Let centripetal acceleration be a_(c):

 \therefore \: a_{c} =  \dfrac{ {v}^{2} }{r}

 \implies \: a_{c} =  { \bigg( \dfrac{v}{r} \bigg) }^{2}  \times r

 \implies \: a_{c} =  { \omega }^{2}  \times r

 \implies \: a_{c} =  {2 }^{2}  \times 2

 \implies \: a_{c} =  8 \: m {s}^{ - 2}

So , centripetal acceleration is 8 m/.

  • Please note that the options given in the question are wrong.

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